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The angle x lies in the interval 2≤x≤pi, and sin² x = 8/9. Determine the value of cos x/2 and sin3x
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i already got that part... would that mean that for cosx/2 i would so whatever cosx equals and then just divide it by two ? :S
yes
really? :S
mhm
so cos x = (r001)/(root)9... i would just to that over 2?
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sorry i meant root1
yes
its wrong ):
what did you get?
got 1/6
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but its (root3)/3
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