Question

help plz

\[3ax+b if x \le 0\]

\[e ^{z (az+b)} if x > 0\]

calculate a and b ...if is derivable

Answer 1

for being derivable,it must be continuous

so f(0-) = f(0) = f(0+) .....(1)

also,
f'(0-) = f'(0) = f'(0+) ...(2)

2eqns, 2 variables..

Answer 2

\[f'(x) = 3a \]
\[f'(x) =2az+b\]

Correct?

Answer 3

nopes..
done 2nd part incorrectly..
also why is z there? is that a typo ? am assuming that should be x.

Answer 4

no is z not x

Answer 5

hmm..
whats the relation between z and x ?
i'd still say its a typo..
z and x are neighbors on a keyboard !

Answer 6

its actually unclear if that's z or x
z makes no sense,has to be x

Answer 7

is z

Answer 8

@Yahoo!

Answer 9

...

Answer 10

how can solve ?

Answer 11

equate functions at 0
equate derivatives at 0

AND THAT, MY DEAR FRIEND,,, IS x !!!

Answer 12

if you take it as z, the derivative of that comes in the form of dz/dx.. which is where we will get stuck..

Answer 13

hmmm

Answer 14

ok leave this question

\[\lim_{x \rightarrow 2^{-}} 9x-3/ x ^{2} - 2x\]

Answer 15

??

Answer 16

3(3x-1)/x(x-2)

x<2
so it should go to -inf ..right ?

Answer 17

and dont leave that question,
i can bet that what i was trying to say for that, am 110% right !

Answer 18

dear is z ...not x

Answer 19

maam thats a misprint
i'd give 2 good logics :
1) z makes it senseless sin relation between z and x is not known
2) z and x, are next to each other on keyboard, so there is, some probability, that there was a typing error.

also, in your screenshot, clarity about z and x is not feasible..

Answer 20

that question was entry test

Answer 21

am not gonna argue further!
i'd like someone other to enlighten us here!

Answer 22

it is impossible....

Answer 23

ok then solve this quest @gk_goel

Answer 24

@Muskan which quest??

Answer 25

is it in english?? @Muskan

Answer 26

no is spanish
calculate a and b

Answer 27

@gk_goel