Four feet of wire is to be used to form a square and a circle. How much of the wire should be used for the square and how much should be used for the circle to enclose the maximum total area?
ok so
Don't help me if you don't want to. You don't have to...
jus give me a sec dont rush the right answer
This is Calculus question, I noticed you asked a question "what is -5/6 + 1/3 " I don't think you can handle my problem. Thanks, though.
Length for the circle = 2 pi x 0.4829 = 3.0342ft Length for the square = 4 - 3.034 = 0.9658 ft
ohh yes and jst fyi always ask those kind of questions because i love to giv out medals
im a nice person
Frankly, that's stupid, but ok. Your answer is wrong, by the way. I have answer key, I just don't know how to get this this answer...
what are the answers then, he choices
All of wire should be used for the circle to enclose the maximum total area. I just don't know how to prove it.
It's not multiple choice, it's free response.
Mmm, seem a wee bit tetchy Geerky42. The proof is simple a sircle encloses the max. area with the smallest perimeter (circumference).
I don't know if I have to show work for this question, though. I used calculus and my work said that I have to use some wire for square, I don't understand why I end up like that. Here's my work if you are interested.
Hopefully everyone can read it.
Let; A = total area X = side of square R= radius of circle A= x^2 +pi r^2 2xdx + 2pi rdr = 0 dx/dr = -pi r/x L = 4x + 2pi r 4dx + 2pi dr = 0 dx/dr =- pi/2 -pi/2 =- pi r/x x =r/2 4 = 4(r/2) +2 pi r 4 = 2r(1+pi) r = 2/(1+pi) = 2/4.1416 = 0.4829 ft Length for the circle = 2 pi x 0.4829 = 3.0342ft Length for the square = 4 - 3.034 = 0.9658 ft
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hello
Our answers are not the same, yet we are both wrong.
????????????????? what grade are you in and what school do you go to
I'm junior at public high school.
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Can you help me, please? @zepdrix @hartnn @RadEn
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