Question

Integrate by using the substitution u = 2x -1 for ∫ sqrt 2x+1 dx from 0 to 2

Answer 1

\[du = 2 dx\]

Answer 2

\[dx = 0.5du\]

Answer 3

do you mean u=2x+1 ? or sqrt{2x-1} ?

Answer 4

\[0.5 \int_{0}^{2} \sqrt{u} du\]The question is wrong, and whatever the question is, this is true