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OpenStudy (anonymous):
Integrate by using the substitution u = 2x -1 for ∫ sqrt 2x+1 dx from 0 to 2
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Parth (parthkohli):
\[du = 2 dx\]
Parth (parthkohli):
\[dx = 0.5du\]
hartnn (hartnn):
do you mean u=2x+1 ? or sqrt{2x-1} ?
Parth (parthkohli):
\[0.5 \int_{0}^{2} \sqrt{u} du\]The question is wrong, and whatever the question is, this is true
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