Question

solve trigonometric equation

Answer 1

\[\tan ^{2}x sinx-sinx=0\]
i got to sinx(tan^2x-1)=0 but dont knpw what to do next

Answer 2

yup go little furhther
that either sinx=0 or tan^2x-1=0

Answer 3

but for tan^2x-1=0 use tan^2x=(1-cos2x)/(1+cos2x)

Answer 4

so x=sin^-1(0)

Answer 5

why would we do that for cos?

Answer 6

if sinx=0
then x= m* pi where m is any integer...

Answer 7

can you take sinx out as a common factor in sin2x-sinx=0?