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If \(\LARGE{a^{1/2}+b^{1/2}-c^{1/2}=0}\) then the value of \(\LARGE{(a+b-c)^2=?}\)
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Plz help :)
a^1/2 + b^1/2 -c^1/2 =0 a^1/2 + b^1/2 =c^1/2 Squaring both sides gives, a+2(ab)^1/2 + b =c a+b-c = 2 (ab)^1/2 So, (a+b-c)^2 = { 2 (ab)^1/2 }^2 = 4ab
\(a+b-c=-2(ab)^{1/2}\)
Well...I gt it thanx a lot dude :)
oh yes.... But the final answer is same
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