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Identify the 8th term of the geometric sequence -2, -12, -72 ... a.-3,359,232 b. -559,872 c. 559,872 d. 3,359,232
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\[{\rm A}_n = {\rm A} \times r^{n - 1}\]
A= first term =-2 r=Geometric ratio = -12/(-2) =6
Now, find A_8
One may notice that \({\rm A} = -2\) and \(r = \dfrac{\rm A_2}{\rm A_1} = 6\)
ive already tried solving it myself it just wasnt working out
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\[A _8 = -2 \times 6^{8 - 1}\]
is the answer b?
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