Question

using the L'Hopital's rule, please solve

lim e^4x +1 - 4x / x^2
x->0

Answer 1

Find d(e^4x+1-4x)/dx
and d(x^2)/dx

Answer 2

but it's not 0/0 right so what do i do ? @sauravshakya

Answer 3

d(e^4x+1-4x)/dx
=4e^4x -4
AND
d(x^2)/dx
=2x

Answer 4

Now, Lets use L'Hospital Rule again

Answer 5

d(4e^4x -4)/dx
=>16e^4x
And
d(2x)/dx
=>2

Answer 6

So,