Question

Find the equation of the circle with center at (-3, 1) and through the point (2, 13).

Answer 1

Equation of a circle is

(x-h)^2+(y-k)^2=r^2

(h,k)= center
r=radius

you can plug in the center (h,k) and the point you have (x,y) and solve for the radius

then youll have what you need to write the equation

Answer 2

(2+3)^2+(13-1)^2=r^2

Answer 3

Solve for r