Question

$6,000 dollars is invested in two different accounts earning 3% and 5% interest. At the end of one year, the two accounts earned $220 in interest. How much money was invested at 3%?

$2,000
$3,000
$4,000

Answer 1

i think 2,000

Answer 2

$4000.

Answer 3

oh well sorry :p

Answer 4

\[$4000\times \frac{ 3 }{ 100 }=$120\]
\[$2000\times \frac{ 5 }{ 100 }=$100\]

Answer 5

Total amount invested= $6000
$4000+$2000=$6000
Total interest earned in one year= $220
$120+$100= $220
Therefore, $4000 was invested at 3%p.a. (per annum)