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Mathematics 17 Online
OpenStudy (anonymous):

Determine the number and type of solutions

OpenStudy (anonymous):

Determine the number and type of solutions for x2 + 4x + 3=0

OpenStudy (anonymous):

x^2+4x+3=0

OpenStudy (anonymous):

Quadratic equations has two solutions

OpenStudy (anonymous):

Unless it is perfect square

OpenStudy (anonymous):

2 Rational?

OpenStudy (anonymous):

Since , b^2 -4ac >0 two rational solution

hartnn (hartnn):

Compare your Quadratic equation with ax^2+bx+c=0 find a,b,c. calculate b^2-4ac if b^2-4ac is positive -----> 2 real roots. if b^2-4ac is 0---->1 repeated real root. if b^2-4ac is negative ---->2 imaginary roots..

OpenStudy (anonymous):

what about this one? What is the range of the graph of y = (x – 4)^2 + 3?

OpenStudy (shubhamsrg):

@sauravshakya b^2-4ac>0 doesnt mean roots are rational.

hartnn (hartnn):

if b^2-4ac is perfect square -----> 2 rational roots.

OpenStudy (anonymous):

I mean real solutions

OpenStudy (anonymous):

ok so its what i though, 2 rational can someone help me on my other question

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