factor. x^3- 343
343 = some number raise to the 3rd power, can you find that number out?
7 ^3?
ok , using the formula ...\[a^{3} - b^{3} = (a-b)(a^{2} + ab + b^{2})\] now can you factor ?
would it be, (x^2-7x^2)(x+7)
no, can you read the formula and try again?
okay
(x-7)(x^2 + 7^2+7) is that right?
not quite, but you're close ...in your problem...a will be x and b is 7 ...so can you try one more time? put in the form of the formula so it's easier for you to recognize.
(x-7)(x^2+ 7x^2 +7x) is that right?
it should be : \[(a-b)(a^{2} - ab + b^{2})\] so \[(x-7)(x^{2} - 7x + 7^{2})\]
my bad...i rewrote the formula wrong...it's +ab ...so the -7x is +7x
thanks hero, and i wrote that formula on the top, just made a mistake rewrote that formula
i'm lost
been working on one question for an hour
(x-7)(x^2 +7b +7b^2) is that right?
okay thank you for your help
wouldn't 7 ^2 come before 7x?
Join our real-time social learning platform and learn together with your friends!