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Mathematics 21 Online
OpenStudy (anonymous):

factor the trinomial completely 4x^3 - 2x^2 - 12x

OpenStudy (cwrw238):

first find the GCF of the 3 terms in the function can you do that?

OpenStudy (anonymous):

2 x

OpenStudy (cwrw238):

right now factor it

OpenStudy (anonymous):

2x (2x^2 -x -6) is that right?

OpenStudy (cwrw238):

= 2x(2x^2 - x - 6) right

OpenStudy (anonymous):

ty

OpenStudy (cwrw238):

yw - how about the function in the parentheses - can that be factored?

OpenStudy (anonymous):

oh, thats not the final answer?

OpenStudy (cwrw238):

maybe not - i'm just checking that out

OpenStudy (anonymous):

ok, i thought it was, now i am confused

OpenStudy (cwrw238):

these sometimes can be factored into the form (2x + a)(x + b)

OpenStudy (cwrw238):

we need 2 numbers a and b whose product is -6 and whose sum (with one of them multiplies by 2) is -1 ( to give the -x)

OpenStudy (anonymous):

so the answer is (2x-1)(2x^2-6)?

OpenStudy (cwrw238):

no i'm talking about the factors of 2x^2 - x - 6 ( in the parentheses)

OpenStudy (cwrw238):

2 * -2 and 1 * +3 will fit the bill because +3 * -2 = -6 and 2* -2 = -4 and 1 * +3 = 3 giving -4 + 3 = -1

OpenStudy (cwrw238):

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