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OpenStudy (anonymous):
factor the trinomial completely
4x^3 - 2x^2 - 12x
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OpenStudy (cwrw238):
first find the GCF of the 3 terms in the function
can you do that?
OpenStudy (anonymous):
2 x
OpenStudy (cwrw238):
right
now factor it
OpenStudy (anonymous):
2x (2x^2 -x -6) is that right?
OpenStudy (cwrw238):
= 2x(2x^2 - x - 6)
right
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OpenStudy (anonymous):
ty
OpenStudy (cwrw238):
yw - how about the function in the parentheses - can that be factored?
OpenStudy (anonymous):
oh, thats not the final answer?
OpenStudy (cwrw238):
maybe not - i'm just checking that out
OpenStudy (anonymous):
ok, i thought it was, now i am confused
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OpenStudy (cwrw238):
these sometimes can be factored into the form (2x + a)(x + b)
OpenStudy (cwrw238):
we need 2 numbers a and b whose product is -6 and whose sum (with one of them multiplies by 2) is -1 ( to give the -x)
OpenStudy (anonymous):
so the answer is (2x-1)(2x^2-6)?
OpenStudy (cwrw238):
no i'm talking about the factors of 2x^2 - x - 6 ( in the parentheses)
OpenStudy (cwrw238):
2 * -2
and 1 * +3 will fit the bill
because
+3 * -2 = -6
and
2* -2 = -4
and 1 * +3 = 3
giving -4 + 3 = -1
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OpenStudy (cwrw238):
|dw:1357681248055:dw|
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