factor the trinomial completely 4x^3 - 2x^2 - 12x
first find the GCF of the 3 terms in the function can you do that?
2 x
right now factor it
2x (2x^2 -x -6) is that right?
= 2x(2x^2 - x - 6) right
ty
yw - how about the function in the parentheses - can that be factored?
oh, thats not the final answer?
maybe not - i'm just checking that out
ok, i thought it was, now i am confused
these sometimes can be factored into the form (2x + a)(x + b)
we need 2 numbers a and b whose product is -6 and whose sum (with one of them multiplies by 2) is -1 ( to give the -x)
so the answer is (2x-1)(2x^2-6)?
no i'm talking about the factors of 2x^2 - x - 6 ( in the parentheses)
2 * -2 and 1 * +3 will fit the bill because +3 * -2 = -6 and 2* -2 = -4 and 1 * +3 = 3 giving -4 + 3 = -1
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