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please help with the process of differentiating 4/ 3x^3
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So you want do calculate\[\frac{d}{dx} \frac{4}{3x^{3}}\]?
ye think so
Ok.\[\frac{d}{dx} \frac{4}{3x^{3}}=\frac{4}{3} \frac{d}{dx} x^{-3}\]Now you can just use the power rule:\[\frac{d}{dx}x^{a}=a \times x^{a-1}\]where a=-3.
Does that help?
ye that makes sense, thanks
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