Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

Help? Suppose that r varies directly with s and inversely with t, and r = 2 when s = 3 and t = 12. What is the value of r when s = 5 and t = 4

OpenStudy (anonymous):

And it's multiple choice. A. 2/5 B.32/5 C.10 D.20

OpenStudy (help!!!!):

wait hold on for 10 minutes and ill figure it out by going into a different tutor site :D

OpenStudy (anonymous):

Mind giving me a link? You know for next time if I can't get help here.

OpenStudy (help!!!!):

it only works in alabama so..................... the state of alabama provides it to the state only so........

OpenStudy (anonymous):

Oh -.- I should probably check if Georgia does anything like that..

OpenStudy (help!!!!):

good idea!!!:D

OpenStudy (anonymous):

Did you find anything?

OpenStudy (anonymous):

On your Alabama tutoring site..

OpenStudy (help!!!!):

they are helping right now

OpenStudy (help!!!!):

okey got it

OpenStudy (help!!!!):

:D

OpenStudy (anonymous):

Yay! Lol. What is it?

OpenStudy (help!!!!):

r varies directly with s and inversely with t means r->s/t

OpenStudy (help!!!!):

|dw:1357701511468:dw|

OpenStudy (help!!!!):

then i would look for K

OpenStudy (help!!!!):

by isolating k from the rest

OpenStudy (help!!!!):

|dw:1357701665109:dw|

OpenStudy (help!!!!):

okey lets restart (the answer is c by the way ) first isolate k. Then plug in the what you know. so k=rxt/s equal tp k=2x12/3.

OpenStudy (help!!!!):

k=8

OpenStudy (help!!!!):

then get r=kxs/t (the original equation ) and plug in what you know

OpenStudy (anonymous):

How did you get k=8?

OpenStudy (help!!!!):

so the question is asking "r varies directly with s and inversely with t" which is r=kxs/t whic you have to isolate k by multiplying by t/s to both sides

OpenStudy (help!!!!):

|dw:1357702199468:dw|

OpenStudy (anonymous):

k=r x 4/5

OpenStudy (help!!!!):

12/3 because we are first using the example

OpenStudy (help!!!!):

k=r x 12/3

OpenStudy (anonymous):

Oh okay, then what?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!