Question

Algebra 2 help please

Answer 1

since 'x' and 'y' vary INVERSELY, the equation will be of the form
\[\large y=\frac{k}{x}\]
you can find the value of 'k' but putting x=2, and y=8 in the above equation.
can you find 'k' ?

Answer 2

k would be 4?

Answer 3

no, how did you calculate that ?
8 = k/2
multiply 2 on both sides, ....k=... ?

Answer 4

i divide 8/2

k=16

Answer 5

but you multiply.

Answer 6

yes, in inverse proportion, we multiply.
so, y=16/x
for first.
For second also, you multiply first 2 values,
n=20, c=5
what you get nc=...? ?

Answer 7

you multiply them together correct?

Answer 8

i got 100

Answer 9

yup, we multiply variables 'x' and 'y'
or in 2nd Q, 'n' and 'c'
to get a constant value everytime,
16 in 1st Q, and 100 in 2nd Q
thats correct! nc=100 :)
any doubts ?

Answer 10

thank you for the help!:)

Answer 11

welcome ^_^