Question

6 miles away from her and 4 miles above from the ground. how many degrees horizontal must she look up to see the plane?

Answer 1

Pythagoras' theorem:
\[c^2 = a^2 + b^ 2\]
so
\[c^2 = 4^2 + 6^2\]
\[c^2 = 16 + 36 = \]
\[c = \sqrt{52} \approx 7.21\]
\[\sin^{-1} \alpha = \frac{ 4}{ 7.21 } \rightarrow \alpha = 33.69^{o}\]