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Mathematics 50 Online
OpenStudy (erinweeks):

SOMEONE PLEASE HELPP ! SO CONFUSED..

OpenStudy (erinweeks):

OpenStudy (erinweeks):

A. 668 m2; 704 m2 B. 645 m2; 740 m2 C. 668 m2; 740 m2 D. 645 m2; 812 m2

OpenStudy (erinweeks):

it gave me no question this is all im guessing find the area and something else!

OpenStudy (anonymous):

well, i can help you.. first you know that the are is the sum of the area of the sides, so you have a rectangle of area (23*12.04) (top view) + you have another rectangle of area (8*23) (back view)+ you have a bottom rectangle of (23*9)+ you have 2 triangles of area (8*9/2) (but are 2 triangles.. the net area of the 2 trianles will be (8*9))... at the end, :\[(23*12.04)+ (8*23)+(23*9)+(\frac{ 8*9 }{2 })+(\frac{ 8*9 }{2 })\approx 740 m\]

OpenStudy (anonymous):

sorry m^2 xD

OpenStudy (erinweeks):

okay so thats the area? but now what else do i have to find?

OpenStudy (klimenkov):

@ankolix Try using \cdot instead of *.

OpenStudy (erinweeks):

so would it be a??

OpenStudy (anonymous):

i think that the are without the triangles ;)

OpenStudy (anonymous):

sorry: *area

OpenStudy (erinweeks):

im confused lol

OpenStudy (erinweeks):

so i was right its a?

OpenStudy (anonymous):

sorry "C" option im lagging so hard :/

OpenStudy (erinweeks):

thank you so muchhhh ! you saved my lifee

OpenStudy (anonymous):

medal ;D

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