Question

How many real zeroes does y = ( x + 8 )^3 + 9 have? (1 point)
1
2
3
0

Answer 1

@hba

Answer 2

I think it only has 1

start with

\[(x + 8)^3 + 9 = 0\]

then

\[(x + 8)^3 = -9\]

and

\[(x + 8) = \sqrt[3]{-9}\]

should be easy to solve for x now...

Answer 3

@campbell_st that didn't show up.

Answer 4

so did you solve for x or just look at the what I'd written..?

Answer 5

Well, I couldn't see what you had written, it says [Math Processing Error], but I don't understand it.

Answer 6

ok.... well is you let y = 0 and solve for x

you will find the number of zeros...