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Mathematics 18 Online
OpenStudy (anonymous):

The figure below shows a square ABCD and an equilateral triangle DPC. Ted makes the chart shown below to prove that triangle APD is congruent to triangle BPC. What is the error in Ted’s proof?

OpenStudy (anonymous):

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@ParthKohli

OpenStudy (anonymous):

@Agent_Sniffles

OpenStudy (anonymous):

ok the angel ADP=BCP=30 No =60

OpenStudy (phi):

I think the 3rd line is close but still wrong. the angles inside the equilateral triangle are 60 but the angles he picked out are 90-60= 30 not 60

OpenStudy (anonymous):

all other is true

OpenStudy (anonymous):

I never really understood proofs..... :(

OpenStudy (anonymous):

|dw:1357766947082:dw| a+c=b+d=90 a=b=60 => c=d=30

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