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The figure below shows a square ABCD and an equilateral triangle DPC. Ted makes the chart shown below to prove that triangle APD is congruent to triangle BPC. What is the error in Ted’s proof?
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@amistre64
@ParthKohli
@Agent_Sniffles
ok the angel ADP=BCP=30 No =60
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I think the 3rd line is close but still wrong. the angles inside the equilateral triangle are 60 but the angles he picked out are 90-60= 30 not 60
all other is true
I never really understood proofs..... :(
|dw:1357766947082:dw| a+c=b+d=90 a=b=60 => c=d=30
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