Question

10k-14=2(13-5k)

Answer 1

Great answer, I'm sure they learned a lot!

Answer 2

\[10k-14=2(13-5k)\]
remember that
\[a(b-c) = ab -ac \]
so our equation becomes
\[10k-14=2(13)-2(5k) = 26 - 10k\]
if we add 10k to both sides, we get
\[10k+10k-14=26-10k+10k\]
\[20k-14=26\]
\[20k-14+14=26+14\]
\[20k=40\]
\[k=2\]

Answer 3

From the openstudy code of conduct: OpenStudy values the Learning process - not the ‘Give you an answer’ process
Don’t post only answers - guide the asker to a solution.

Answer 4

At least show *how* to get the answer!