Question

2 log 4 – log 3 + 2 log x – 4 = 0 I'm trying to solve for x, both my friend and I have apparently gotten the wrong answer...

Answer 1

log16-log3+logx^2=4
log[(16+x^2)/3]=4
(16+x^2)/3=10^4
16+x^2=3*10^4
x=sqrt(3*10^4-16)

Answer 2

if you are asking this 2 log 4 – log 3 + 2 log( x – 4) = 0
then
log16-log3+log(x-4)^2=0
log[(16+(x-4)^2)/3]=0
(16+(x-4)^2)/3=10^0=1

16+(x-4)^2=3
(x-4)^2=-13
no real solution..

Answer 3

173.158886575

Answer 4

Ohhhhh that makes much more sense, the first one and yeah we just made the mistake of using a calculator which I realize now doesn't work for something with x in it, so we got completely the wrong answer. Thanks for your help!

Answer 5

np..