Question

Determine the absolute extrema of the function and x-value in the closed interval where it occurs. Function: g(x)=x^1/3. Interval: [-1, 1]

Answer 1

\[g(x)=\sqrt[3]{x}\] is a strictly increasing function

Answer 2

no need for any fancy calculus for that right? it is more or less obvious that the larger a number is, the larger the cubed root of that number is
so the min is at -1 and the max is at 1

Answer 3

Oh my gosh, you're right! I was making this way too difficult. Haha, thank you!