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HELP! prove tan5utan3u=(tan^2*4u-tan^2*u)/(1-tan^2*4u*tan^2u
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you know tan(A+B) and tan(A-B) formula ?? write 5u = 4u+u 3u=4u-u and use the formula.
\[\tan(A+B) = \frac{\tan A+\tan B}{1-\tan A.\tan B}\] put, A=4u, B=u here. \[\tan(A-B) = \frac{\tan A+\tan B}{1+\tan A.\tan B}\] put, A =4u, B =u here also, then just multiply both the equations, and you'll get your result.
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