If g(x) = 1-3x and a = -1, find Ag(x) by using area formulae and properties of integrals using these cases: a) case 1: x -1 b) case 2: -1=

Question

If g(x) = 1-3x and a = -1, find Ag(x) by using area formulae and properties of integrals using these cases:
a) case 1:  x > -1
b) case 2:  -1=<x=<1/3
c) case 3: x < -1

anonymous · Answer

So I am having difficulty in finding out the answer for case #2. I have found out the answers for case 1&3 which is -3/2x^2 + x + 5/2 which should be the answer for all but I don't know how to find case #2

anonymous · Answer

For case #2 I keep getting -1/6 + x -3/2x^2 which is the incorrect answer. It should be -3/2x^2 + x + 5/2

anonymous · Answer

Here's my work for case #2: -(1/2(1/3-x)(1-3x))

anonymous · Answer

Here's my graph for case #2:|dw:1357814408875:dw|