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OpenStudy (anonymous):
Simplify the expression: cot x sin x - sin (pi/2 - ) + cos x
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OpenStudy (aravindg):
sin (pi/2 - ) ??
OpenStudy (anonymous):
Oh corry sin (pi/2 -x)
OpenStudy (anonymous):
sorry*
OpenStudy (aravindg):
sin(pi/2-x)=cos x
OpenStudy (aravindg):
substitute that and you will get the answer!
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OpenStudy (anonymous):
wait I'm not sure I get... so substitute sin(pi/2 -x) so that would be (1-0)? so 1?
OpenStudy (anonymous):
I don't get it :(
OpenStudy (anonymous):
@Val97 sin(pi/2)=1 but sin(pi/2-x)=cosx
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