What is the equation of the line in slope-intercept form that passes through the point (3, –5) and is perpendicular to the line y = 3x – 6?

y = –3x – 4

y = –3x + 4

y = negative one-thirdx – 4

y = negative one-thirdx + 4

Question

What is the equation of the line in slope-intercept form that passes through the point (3, –5) and is perpendicular to the line y = 3x – 6?

y = –3x – 4

y = –3x + 4

y = negative one-thirdx – 4

y = negative one-thirdx + 4

anonymous · Answer

How do I find b in y=mx+b??

anonymous · Answer

never mind... I figured it out :D