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graph the function, identify the axis of symmentry. promblem in comments
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\[y=(x+3)^{2}-4\]
Ohh goody, its already in vertex form which means you can easily identify the axis of symmetry and graph it. =D so vertex form is y=a(x-h)^2+k x=h is the axis of symmetry, comparing this to your equation can you identify it?
3but idk how to graph it.
The sign changes so its x=-3 -3 is also the x coordinate of the vertex, k would be the y coordinate of the vertex so (-3,-4) is the vertex
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