Question

How

can I get 2(n+1)=2^(n+1) - 2 to equal the same thing on both sides?

Answer 1

whats the ^ on the 2nd part?

Answer 2

\[2(n+1)=2^{n+1}-2\]

Answer 3

2(n+1)+2=2^(n+1)
2n+4=2^(n+1)
log(2n+4)=(n+1)log2
(log(2n+4))/(n+1)=log2
log((2n+4)^(1/(n+1))=log2

((2n+4)^(1/(n+1))=2