Question

Find all solution in the interval [0, 2pi).

sec^2x – 2 = tan^2x

Answer 1

A) No Solution
B)\[x=\frac{ \pi }{ 3 }\]
C)\[x=\frac{ \pi }{ 4 }\]
D)\[x=\frac{ \pi }{ 6 }\]

Answer 2

I think it's C.

Answer 3

x = +-pi/4

Answer 4

Medal if you want :D

Answer 5

Do you mind explained a bit how to do it? :o)

Answer 6

explaining*