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QUESTION GOING TO BE POSTED BELOW HELP PLS :D
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evaluate \[a + \frac{ 1 }{ a }\] for these values of A
\[\frac{ 3 - \sqrt{3} \ }{ 3 + \sqrt{3} }\] = A
i know you need to substitute A into the equation but then im lost
\[\frac{ 3 - \sqrt{3} }{ 3 + \sqrt{3} } + \frac{ 1 }{ \frac{ 3 - \sqrt{3} }{ 3 + \sqrt{3}} }\]
Hmm, well for the right part remember dividing by a fraction is same as multiplying by reciprocal blah blah So youve now got \[(3-\sqrt{3})/(3+\sqrt{3}) + (3+\sqrt{3})/(3-\sqrt{3})\]
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oh thanks so much i FORGOT THAT
i reckon i can solve that now :) dont u love my new pic the cat?
Yep the cat picture is nice. I was hoping youd be good from here because i have no idea. lolol
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