Mathematics
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OpenStudy (anonymous):
sqrt 250 x^16 / sqrt 2x
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OpenStudy (kuoministers):
hi :)
OpenStudy (anonymous):
hey! lol can you help me with this problem
OpenStudy (kuoministers):
\[ \frac{ \sqrt{250x ^{16}} }{ \sqrt{2x }}\]
This is the question right?
meoowwwwww
OpenStudy (anonymous):
yep!
OpenStudy (kuoministers):
so we need to simply this right?
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OpenStudy (anonymous):
yep!!
OpenStudy (kuoministers):
what 2 numbers can u break down 250 like using numbers such as 4, 9, 36, 81(theres a lot more)
OpenStudy (kuoministers):
you know how to simply a surd e.g
sqrt 12
is
2 sqrt 3
OpenStudy (anonymous):
would it be 10 and 25?
OpenStudy (kuoministers):
:) yes!!
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OpenStudy (kuoministers):
and sqrt x^16 would be?
e.g sqrt x^14
is 7x
OpenStudy (anonymous):
4x?
OpenStudy (kuoministers):
hmm not really its half.. like sqrt x^2 is only x which is half right?
so it would be 8x
OpenStudy (anonymous):
oh alright ya that makes more since!
OpenStudy (anonymous):
so what would the equation look like as of right now?
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OpenStudy (kuoministers):
actually the sqrt x^14 was wrong :P
OpenStudy (anonymous):
so what would it be then? lol
OpenStudy (kuoministers):
\[\sqrt{x^{14}} \] would be..
OpenStudy (kuoministers):
\[x \sqrt{x^{7}}\]
cause x^2 times x^7 gives you
sqrt x^14
OpenStudy (anonymous):
so would \[\sqrt[x]{x^8}\]
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OpenStudy (anonymous):
or i mean x sqrt x^8
OpenStudy (kuoministers):
\[\frac{ \ 5x ^{8} { \sqrt{10 ^{}}}{ } }{ \sqrt{2x} }\]
OpenStudy (kuoministers):
wow that took forever :P
meoowwww
OpenStudy (anonymous):
lol so thats the final answer?
OpenStudy (kuoministers):
ok my bad but i remembered!!!
sqrt x^16 is x^8!!!
and sqrt x^14 is x^7!!!
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OpenStudy (kuoministers):
it should be!!!
if not pls tell me :P
but it should be right
OpenStudy (anonymous):
Alright thank you a lot!
OpenStudy (kuoministers):
np!! dont forgot the medal :D
OpenStudy (kuoministers):
and thanks to you for being patient with a cat
OpenStudy (anonymous):
np! and i wont1
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OpenStudy (anonymous):
wont! lol