Question

Integral:
arctanx/(1+x^2) dx

Answer 1

I get (arctanx)^2/2 but wolfram gives something else

Answer 2

http://www.wolframalpha.com/input/?i=d%2Fdx+arctanx%2F%281%2Bx%5E2%29

Answer 3

\[\int\limits \frac{\tan^{-1}x}{1+x^2}dx\]just to dbl check. This the right problem?

Answer 4

yes

Answer 5

yeah that's what I am getting as well

Answer 6

u-substitute for arctanx

Answer 7

Oops.. i just realized I put d/dx instead of the integral sign on wolfram -_- I'm tired :(

Answer 8

@kirbykirby

do u wanto integrate or differentiate

Answer 9

lmao... noticed that

Answer 10

integrate

Answer 11

@@kirbykirby
u have integrated it correctly

Answer 12

so do the u sub

Answer 13

\[\frac{d}{dx} arctanx=\frac{1}{1+x^2}\]which is eactly what we have there!!

Answer 14

Yeah thanks everyone :)!! I wish I could give a medal to everyone

Answer 15

I'm so silly lol

Answer 16

hey tyhanks guys @kirbykirby, I'm assuming you posted this in response to my orignal post?

Answer 17

or we're in the same class lol

Answer 18

What's your original post?

Answer 19

@egr2b I don't know if I know you o_O?

Answer 20

http://openstudy.com/updates/50ef9dc8e4b0d4a537ce1be4

Answer 21

Oh I didn't even know you posted that haha!

Answer 22

Maybe we are in the same class ._. this is weird loool

Answer 23

lol... good luck then