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Simplify -1/x+2 + x-1/4/ x+3/x+2
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is it x-1/4 + x+3/x+2?
or are there fractions in the fraction?
\[\frac{ \frac{ \frac{ -1 }{ x+2 }+\frac{ x-1 }{ 4 } }{ x+3 } }{ x+2 }\]
\[=\frac{ \frac{ -4+(x-1)(x+2) }{ 4(x+2) } }{ \frac{ x+3 }{ x+2 } }\] \[=\frac{ -4+x^2+2x-x-2 }{ 4(x+2) }\times \frac{ x+2 }{ x+3 }\] \[\frac{ x^2+x-6 }{ 4 }\times \frac{ 1 }{ x+3 }\] \[\frac{ (x+3)(x-2) }{ 4 }\times \frac{ 1 }{ x+3 }\]
\[\frac{ x-2 }{ 4 }\]
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