#1: The theoretical yield of a reaction is 5.00 moles of potassium permanganate (KMnO4). If the reaction actually produces 695.2 g KMnO4, what is the percent yield of the reaction?

A. 78%

B. 83%

C. 88%

D. 120%

**idk :( which is it? @UnkleRhaukus :)

Question

#1: The theoretical yield of a reaction is 5.00 moles of potassium permanganate (KMnO4). If the reaction actually produces 695.2 g KMnO4, what is the percent yield of the reaction?

A.       78%

B.      83%

C.     88%

D.    120%

**idk :( which is it? @UnkleRhaukus  :)

anonymous · Answer

#2: The equation for the formation of water from hydrogen gas and oxygen gas is 2H2 + O2  2H2O. How many grams of water can be made from 160 g of oxygen gas?

A.       160 g

 B.      180 g

  C.     320 g

   D,.    405 g

**idk this one either :/

anonymous · Answer

idk :(

anonymous · Answer

is it 4?? or is it 3? ;/

anonymous · Answer

idk how to do that :/ can u pls show me? and this if for #1 right>?

anonymous · Answer

#3: Consider the hydrazinenitrogen tetroxide rocket fuel reaction:
2N2H4 + N2O4  3N2 + 4H2O
How many grams of N2H4 will be consumed by 92 g of N2O4?

A.       128 g

 B.      64 g

  C.     32 g

   D.    16 g

**my answer; C. 32 g

is that right?? not too sure =/

anonymous · Answer

#4: Consider this reaction:
N2 + 3H2  2NH3
Suppose you have 2.0 L of nitrogen. How many liters of hydrogen do you need for a complete reaction? (One mole of any gas occupies 22.4 L under certain conditions of temperature and pressure. Assume those conditions for this question.)

A.       2.6 L

 B.       6.0 L

  C.     9.0 L

 D.      10.0 L

**my answer: A. 2.6 L

is that right?? again, not too sure :/

unklerhaukus · Answer

one at a time please

anonymous · Answer

#5: A reaction produces 10.5 L of oxygen, but was supposed to produce 1 mol of oxygen. What is the percent yield? (One mole of any gas occupies 22.4 L under certain conditions of temperature and pressure. Assume those conditions for this question.)

A.       22%

 B.      47%

   C.    67%

    D.   94%

**my answer; B. 47%

is that right?

anonymous · Answer

oh oaky sorry!! btw, that's all the questions so ill just leave em there and we can scroll up! is that oaky?

and oaky i seee... what do i do next?

unklerhaukus · Answer

ok,

anonymous · Answer

so what do i do now? and is this #1 right?

unklerhaukus · Answer

#1:
how many moles is $695.2 [\text g] \text{KMnO}_4$  ?
first you need to work out the molar mass of $\text{KMnO}_4$
$$M_{\text{KMnO}_4}=M_{\text K}+M_{\text{Mn}}+4M_{\text O}=$$

unklerhaukus · Answer

$$M_{\text K}=39 \quad\text g /\text{mol}$$$$M_{\text {Mn}}=55 \quad\text g /\text{mol}$$$$M_{\text {O}}=16 \quad\text g /\text{mol}$$

anonymous · Answer

okay so what's after that? how do i see what percentage it is?

unklerhaukus · Answer

have you worked out the molar mass of  KMnO4?

anonymous · Answer

noo ;( idk how to do that :(

unklerhaukus · Answer

$$M_{\text{KMnO}_4}=M_{\text K}+M_{\text{Mn}}+4M_{\text O}=$$

anonymous · Answer

ohh but idk what to do there :/ at least not on this one :(

unklerhaukus · Answer

maybe it is best to try these when you aren't so tired

anonymous · Answer

oaky :) i will!! thank youuu :D