the coordinates of the vertices of triangle abc are A (4,1) B (-3,2) C (0,k).given that the area of ABC is 12.sq units,find the value of k
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OpenStudy (anonymous):
I guess the one thing you are going to need is an equation that will give you an unknown. Since you have the area and know some lengths I suggest you use
\[\frac{1}{2}*b*h= area\]
OpenStudy (anonymous):
where b= base length
and h = length of height
OpenStudy (anonymous):
mmk
OpenStudy (anonymous):
Does that give you more of the direction you have to take to answer this question or do you need some more help?
OpenStudy (anonymous):
cn u solve it for me :P
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OpenStudy (anonymous):
Screw that I'm not doing your HW.
OpenStudy (anonymous):
:D
OpenStudy (anonymous):
Not even funny. Don't insult me by telling me to do your work when I took the time to give you a hint to doing the problem. You didn't even bother to do it.
OpenStudy (anonymous):
noo i didn't mean it ma frnd i am srry thx buddy
OpenStudy (anonymous):
nooo :/
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OpenStudy (anonymous):
@RyanL. its enough i dnt need ur help anymre
OpenStudy (anonymous):
ohhk
OpenStudy (anonymous):
cn u solve it 4 mei i hav test 2marrow plsss @Hero