Question

pleasee help

What is the length of the major axis of the ellipse shown below?

(x-7)^2/4+(y+3)^2/16=1

Answer 1

\[\frac{(x-7)^2}{4}+\frac{(y+3)^2}{16}=1\]
semimajor axis = \sqrt{16} = 4, so the major axis length will be 2*4 = 8