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In the system shown below, what are the coordinates of the solution that lies in quadrant III? Write your answer in the form (a,b) without using spaces.
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Same thing as last time. Solve for x^2 in the top equation, plug it into the second and solve for y. Quadrant III has a negative x value and a negative y value
is (-2,-5) correct? @BluFoot
Yup perfect!
thanks so much! :)
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You can check it by plugging in the point into both equations. Plug in -2 as x and -5 as y, and if both equations work out then you're good.
can you help me with one more?
sure
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