What is the average value of the function on the interval from x=-3 to x=-1

Question

ksaimouli · Answer

ksaimouli · Answer

@amorfide

mathmate · Answer

The average value of the function would be
$\large \int_{-3}^{-1} g(x)dx $
Can you do the integration?

ksaimouli · Answer

i exactly did that does not work

mathmate · Answer

Sorry, the integral should be divided by (-1- (-3))=2 to get the average value.

ksaimouli · Answer

?

mathmate · Answer

what did you get?

mathmate · Answer

Average value = $ \large \int_a^b f(x)dx / (b-a) $

ksaimouli · Answer

28/6

mathmate · Answer

You have the correct answer, but you need to simplify it (14/3) and divide by 2 which comes from (-1-(-3)), the length of interval of integration.

mathmate · Answer

In the end, you should get 7/3.

ksaimouli · Answer

ya thx

mathmate · Answer

@oldrin.bataku  I think there was a mix-up with the substituted limits of integration.

ksaimouli · Answer

i got it

mathmate · Answer

That's good!  Keep it up!