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What is the average value of the function on the interval from x=-3 to x=-1
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@amorfide
The average value of the function would be \(\large \int_{-3}^{-1} g(x)dx \) Can you do the integration?
i exactly did that does not work
Sorry, the integral should be divided by (-1- (-3))=2 to get the average value.
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?
what did you get?
Average value = \( \large \int_a^b f(x)dx / (b-a) \)
28/6
You have the correct answer, but you need to simplify it (14/3) and divide by 2 which comes from (-1-(-3)), the length of interval of integration.
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In the end, you should get 7/3.
ya thx
@oldrin.bataku I think there was a mix-up with the substituted limits of integration.
i got it
That's good! Keep it up!
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