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Linear Algebra
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Point-Slope Form: "Graph each equation."
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#5. y-2=2(x+3) #6. y+3=-2(x+1) #7. y+1=-3/5(x+5)
|dw:1358042338363:dw|
How do you show your work?
i made a mistake !!!!!
:O
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buts its k i'll tell u how to plot
yeah i need to show my work too
for the given equation u got to make up a table for getting the points
huh.?
?
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for the given equation u got to make up a table for getting the points when u put x=0 in the given equation y value becomes 8 so , (0,8) is one of the points in the given straight line when u put y=0 in the given equation x value becomes 3 so, (3,0 ) is also one of the points in the given straight line|dw:1358043164412:dw|
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