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please helppppp! I'm horrible at math :/ In the below system, solve for y in the first equation. x + 3y = 6 2x – y = 10 one thirdx + 2 negative one thirdx + 6 –x + 2 negative one thirdx + 2
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y = -1/3x + 2 ?
looks right to me!
Is your last choice.
oh! i missed a few steps...or did something wrong i guess. thank you <3
Use the substitution method to solve the following system of equations. 4x – y = 3 7x – 9y = –2 (1, 1) (6, –3) (6, 1) (1, –3)
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would it be (1,1)?
@Hero
(1,1) is right for that one
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