Find the values of x for all points on the graph of f(x)=x^3-2x^2+5x-16 at which the slope of the tangent line is 4.

Question

anonymous · Answer

Take the derivative, set it equal to 4, then solve for x.

anonymous · Answer

The derivative I found is 3x^2 -4x +5. 
After that I make the whole thing equal to four? 
Then I would subtract the 5 but after that what?

anonymous · Answer

solve the resulting quadratic equation for $x$

anonymous · Answer

$$3x^2-4x+5=4$$
$$3x^2-4x+1=0$$ etc

anonymous · Answer

i think you are lucky  here in that this problem has been cooked so the quadratic factors, but you can always use the quadratic formula to solve any quadratic equation

anonymous · Answer

@satellite73 is helping you the way I would've.