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Chemistry
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Two atoms have the electron configurations 1s2 2s2 sp6 and 1s2 2s2 2p6 3s1. The first ionization energy of one is 2080 kJ/mol and that of the other is 496 kJ/mol Match each ionization energy with one of the given electron configurations. Justify your choice. The answer is 1s2 2s2 2p6: 2080 k/mol I can't figure out how to get this answer. Please help!! :(
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