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Find all points at which the graph of f(x)=x^3-3x has horizontal tangent lines.
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horizontal tangent line means the slope of the graph is 0..so by differentiating the function we get 3x^2-3 which is the rate of change or slope of the function ..so equating this to be 0 you get 2 values of x for which the function has a horizontal tangent!
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