Question

Please Help!


Find all real solutions of the equation.
1/x-1-2/x^2=0

Answer 1

Here's the start:
\[\frac{ x^2-2(x-1) }{x^2(x-1)}=0\]

Answer 2

so then would it be \[x^2-2x+1=0 \]

Answer 3

-2(x-1) = -2x + 2

Answer 4

How did u get that stiwan

Answer 5

hello

Answer 6

No, you are correct @x0hill. Distribute the 2 across the parenthesis now.

Answer 7

what do you mean distribute the 2

Answer 8

Well, you have: \[x^2-2(x-1) = x^2... = 0\]