The perimeter of a rectangle is 28 ft. the length is 6
ft longer than the width, find the dimensions?

The formula for the perimeter, P, of a rectangle is 2L + 2W = P
Since the length is 6 feet longer, W = L - 6.

Question

The perimeter of a rectangle is 28 ft. the length is 6
ft longer than the width, find the dimensions?



The formula for the perimeter, P, of a rectangle is 2L + 2W = P
Since the length is 6 feet longer, W = L - 6.

anonymous · Answer

l=6 ft longer than w so l=6+w
28=2w+2(6+w)
28=2w+12+2w
28=4w+12
16=4w
4=w
l=6+w
l=10
28=2(10)+2(4)
28=20+8
28=28

anonymous · Answer

So if I were to write the first equation would it be 2L+2W= 28 then the second equation l=w+6??

would it be 28=4L-12
                 +12      +12

                          40=4L
                                 L= 10 ?