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Solving Systems Using Substitution???Am I doing this right???
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y=8-x and 7=2-y...2-(8-x)??
16-2x=7...Is this correct???
the original equations are y = 8-x and 7 = 2-y ? is there an x in the second equation?
Yes those are the original equations.
is there an x in the second equation?
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After the orignal equations,I substituted teh y in teh second equation and got 2-(8-x)=7.No there's no x in teh second equation.
Then I used the distributive proprety to get 16-2x=7.
If there are no x terms in 7 = 2-y, then why not solve for y 7 = 2-y 7 - 2 = -y 5 = -y -y = 5 y = -5
then plug this into y = 8-x to get -5 = 8-x then solve for x -5 = 8 - x -5 - 8 = -x -13 = -x -x = -13 x = 13
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