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Mathematics 7 Online
OpenStudy (anonymous):

How many gallons of 60% antifreeze solution must be mixed with 60 gallons of 25% antifreeze to get a mixture that is 50% antifreeze? You need ___ gallons.

OpenStudy (mertsj):

.6x+.25(60)=.5(60+x)

OpenStudy (anonymous):

Can you explain how you made that equation??

OpenStudy (mertsj):

x is the number of gallons of 60% antifreeze to add. 60 gallons is the amount of antifreeze he is going to add it to. x + 60 is therefore the total number of gallons of antifreeze they will end up with. Tell me if you understand so far.

OpenStudy (anonymous):

yes continue

OpenStudy (mertsj):

The amount of antifreeze in x gallons of 60 percent solution is .60x Do you understand that?

OpenStudy (anonymous):

Yep, Go on...

OpenStudy (mertsj):

Likewise the amount of antifreeze in 60 gallons of 25% solution is .25(60) and the amount of antifreeze in the final (60+x) gallons which is 50% antifreeze if .5(60+x)

OpenStudy (mertsj):

antifreeze you start with plus antifreeze added = antifreeze final

OpenStudy (anonymous):

Excellent explanation.!! Thanks..,

OpenStudy (mertsj):

yw

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