The sum of the digits of a certain two-digit numberis 8. Reversing its digits increases the number by 36. Find the Number.
2 digit number has a "tens place" and a "ones place" let x be first digit, y second digit value of number is 10x +y ..... value of reverse order is 10y +x so x+y = 8 and (10x +y) +36 = 10y +x now simplify and solve system of 2 equations
how do you simplify it?
combine like terms so it is in form: Ax +By = C
ok i got 9x-9y=-36, is that right?
correct ... now solve system using elimination (or addition method)
wait you could use substitution as well :|
do we eliminate it using x+y=8?
if you are unfamiliar with that method, then just use substitution: solve for y in 1st equation , then plug it into 2nd equation
ok but im using the equations, x+y=8 and 9x-9y=-36?
yes
is y=12 and x=8?
no, x+y = 8 .... 12+8 = 20 ??
also a digit is 0-9 .... 12 is 2 digits not one
y=6 x=2
yes, correct so number is 26
Thank You
yw
Join our real-time social learning platform and learn together with your friends!