Question

solve for x: ln(x^2 +1) - 3lnx= ln2?

Answer 1

3lnx=ln(x^3)
then by the propertie lna-lb=ln(a/b)
ln((x^2+1)/x^3)=ln2
That means
(x^2+1)/x^3 = 2
then solve that, x=1